3925. Concatenate Array With Reverse

You are given an integer array nums of length n.

Construct a new array ans of length 2 * n such that the first n elements are the same as nums, and the next n elements are the elements of nums in reverse order.

Formally, for 0 <= i <= n - 1:

• ans[i] = nums[i]
• ans[i + n] = nums[n - i - 1]

Return an integer array ans.

class Solution {
public:
    vector<int> concatWithReverse(vector<int>& nums) {
        for(int i = nums.size() - 1; i >= 0; i--) nums.push_back(nums[i]);
        return nums;
    }
};