[Codeforces] Round #533 (Div. 2) C. Ayoub and Lost Array

Codeforces Round #533 (Div. 2) C. Ayoub and Lost Array

  • Time : O(n)
  • Space : O(n)
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#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

using namespace std;

struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};

// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);

// alias
using ll = long long;
using ld = long double;
using ull = unsigned long long;

// constants
const ld PI = 3.14159265358979323846; /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 202020;
const ll mod = 1e9 + 7;

// typedef
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef pair<string, string> pss;
typedef vector<pss> vpss;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;

// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define ASCEND(a) iota(all(a),0)
#define sz(x) ll((x).size())
#define pyes cout<<"YES\n";
#define pno cout<<"NO\n";
#define pneg1 cout<<"-1\n";
#define ppossible cout<<"Possible\n";
#define pimpossible cout<<"Impossible\n";
#define CASE(x) cout<<"Case #"<<x<<": ";

// utility functions
template <typename T>
void print(T &&t) { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<" ";cout<<"\n";}
void fileIO() {freopen("input.txt","r",stdin); freopen("output.txt","w",stdout);}
void hackerCupIO() {freopen("/Users/summerflower/Downloads/second_flight_input.txt", "r", stdin); freopen("/Users/summerflower/Downloads/solution.txt","w",stdout);}
//void readf() {freopen("", "rt", stdin);}
template<typename T>
void readv(vector<T>& v){rep(i,0,sz(v)) cin>>v[i];}
void readpll(pll& A) {cin>>A.first>>A.second;}
void readvpll(vpll& A) {rep(i,0,sz(A)) readpll(A[i]); }
void readvall3(vall3& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2];}
void readvvll(vvll& A) {rep(i,0,sz(A)) readv(A[i]);}

// geometry data structures
template <typename T>
struct Point {
T y,x;
Point() {}
void input() {cin>>y>>x;}
};

template<typename T>
struct Circle {
Point<T> center;
T radius;
Circle() {}

void input() {
center = Point<T>();
center.input();
cin>>radius;
}

bool circumference(Point<T> p) {
return (center.x - p.x) * (center.x - p.x) + (center.y - p.y) * (center.y - p.y) == radius * radius;
}

bool intersect(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
return (radius - c.radius) * (radius - c.radius) <= d and d <= (radius + c.radius) * (radius + c.radius);
}
};

ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
ll __lcm(ll x, ll y) { return x / __gcd(x,y) * y; }
ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

ll count(ll n, ll d) {
return n / 3 + (d != 3 ? (n % 3) >= (d % 3) : 0);
}

ll dp[MAX_N][3];

ll helper(ll pos, ll rem, vll& f, ll n) {
if(pos == n) return rem == 0;
if(dp[pos][rem] != -1) return dp[pos][rem];
ll& res = dp[pos][rem] = 0;
rep(i,0,3) res = (res + f[i] * helper(pos + 1, (rem + i + 1) % 3, f, n) % mod) % mod;
return res;
}

ll solve(ll n, ll l, ll r) {
MINUS(dp);
vll freq(3);
rep(i,0,3) freq[i] = count(r,i+1) - count(l-1,i+1);
return helper(0,0,freq,n);
}


int main() {
Code By Sumfi
cout.precision(12);
ll tc = 1;
//cin>>tc;
rep(i,1,tc+1) {
ll n,l,r;
cin>>n>>l>>r;
print(solve(n,l,r));
}
return 0;
}
Author: Song Hayoung
Link: https://songhayoung.github.io/2022/09/06/PS/Codeforces/div2-533-c/
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