[Codeforces] Round #641 (Div. 2) B. Orac and Models

Codeforces Round #641 (Div. 2) B. Orac and Models

  • Time : O(n * p(n))
  • Space : O(n + p(n))
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

struct PairHash {
inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }
};

#define M_PI 3.14159265358979323846 /* pi */
#define MAX_N 202020
#define INF 987654321
#define EPS 1e-9
#define ll long long
#define pll pair<ll, ll>
#define vpll vector<pll>
#define vall3 vector<array<ll,3>>
#define all3 array<ll,3>
#define all5 array<ll,5>
#define vall5 vector<all5>
#define vll vector<ll>
#define vi vector<int>
#define vs vector<string>
#define usll unordered_set<ll>
#define uspll unordered_set<pll, PairHash>
#define umll unordered_map<ll,ll>
#define vvs vector<vs>
#define vvll vector<vll>
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)

ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }

using namespace std;

vll prime;

void primes() {
bool sieve[100001] = {};
memset(sieve, true, sizeof sieve);
for(ll i = 2; i <= 100000; i++) {
if(!sieve[i]) continue;
prime.push_back(i);
for(ll j = i * i; j <= 100000; j++)
sieve[j] = true;
}
}

ll solve(vll A) {
ll n = A.size(), res = 0;

vll dp(n, 1);
for(ll i = n - 1; i >= 1; i--) {
for(auto& p : prime) {
if(i * p >= n) break;
if(A[i] < A[i * p])
dp[i] = max(dp[i], 1 + dp[i * p]);
}
res = max(res, dp[i]);
}

return res;
}

int main() {
ios_base::sync_with_stdio(0);
ios::sync_with_stdio(0);
cin.tie(0);
cout.precision(12);
ll tc = 1;
cin>>tc;
primes();
for (ll i = 1; i <= tc; i++) {
ll n;
cin>>n;
vll A(n + 1);
for(ll j = 1; j <= n; j++) cin>>A[j];
cout<<solve(A)<<endl;
}
return 0;
}
Author: Song Hayoung
Link: https://songhayoung.github.io/2022/06/23/PS/Codeforces/div2-641-b/
Copyright Notice: All articles in this blog are licensed under CC BY-NC-SA 4.0 unless stating additionally.