Codeforces Round #689 (Div. 2, based on Zed Code Competition) B. Find the Spruce
- Time : O(nm^2)
- Space : O(m)
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| #include <bits/stdc++.h>
#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")
struct PairHash {inline std::size_t operator()(const std::pair<int,int> & v) const {return v.first*31+v.second;}};
#define MAX_N 202020
#define INF 987654321
#define EPS 1e-9
#define ll long long
#define pll pair<ll, ll>
#define vpll vector<pll>
#define vall3 vector<array<ll,3>>
#define all3 array<ll,3>
#define all5 array<ll,5>
#define vall5 vector<all5>
#define vll vector<ll>
#define vi vector<int>
#define vs vector<string>
#define usll unordered_set<ll>
#define uspll unordered_set<pll, PairHash>
#define umll unordered_map<ll,ll>
#define vvs vector<vs>
#define vvll vector<vll>
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
using namespace std;
ll solve(vs& A) {
ll res = 0, m = A[0].size();
vll dp(m);
for(auto& r : A) {
for(ll i = 0; i < m; i++) {
if(r[i] == '.') dp[i] = 0;
else dp[i] += 1;
}
for(ll i = 0; i < m; i++) {
ll now = min({dp[i], i + 1, m - i});
for(ll j = 0; j < now; j++) {
if(dp[i + j] >= (now - j) and dp[i - j] >= (now - j)) continue;
now = min(dp[i + j], dp[i - j]) + j;
}
res += now;
}
}
return res;
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
ll tc = 1;
cin>>tc;
for(ll i = 1; i <= tc; i++) {
ll n,m;
cin>>n>>m;
vs A(n);
for(ll j = 0; j < n; j++) cin>>A[j];
cout<<solve(A)<<endl;
}
return 0;
}
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