[AtCoder] F - Operations on a Matrix

F - Operations on a Matrix

  • Time : O(qlogm)
  • Space : O(m + q)
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#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

struct PairHash {inline std::size_t operator()(const std::pair<int,int> & v) const {return v.first*31+v.second;}};

#define MAX_N 252525
#define INF 987654321
#define EPS 1e-9
#define ll long long
#define pll pair<ll, ll>
#define vpll vector<pll>
#define vall3 vector<array<ll,3>>
#define all3 array<ll,3>
#define all5 array<ll,5>
#define vall5 vector<all5>
#define vll vector<ll>
#define vi vector<int>
#define vs vector<string>
#define usll unordered_set<ll>
#define uspll unordered_set<pll, PairHash>
#define vvs vector<vs>
#define vvll vector<vll>
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)

using namespace std;

ll fenwick[MAX_N];
ll t[MAX_N], l[MAX_N], r[MAX_N], v[MAX_N];
vpll eft[MAX_N];
pll qry[MAX_N];
vpll last(MAX_N, {-1, 0});
vll res;

void update(ll n, ll m, ll v) {
while(n <= m) {
fenwick[n] += v;
n += n & -n;
}
}

ll query(ll n) {
ll res = 0;
while(n) {
res += fenwick[n];
n -= n & -n;
}
return res;
}

void solve(ll m, ll q) {
for(ll i = 0, re = 0; i < q; i++) {
if(t[i] == 1) {
update(l[i], m, v[i]);
update(r[i] + 1, m, -v[i]);
} else if(t[i] == 2) {
for(auto& [id, n] : eft[i]) {
res[id] -= query(n);
}
} else {
res[re++] += query(qry[i].second);
}
}
}

void qry1(ll j) {
cin>>l[j]>>r[j]>>v[j];
}

void qry2(ll j) {
cin>>qry[j].first>>qry[j].second;
last[qry[j].first] = {j, qry[j].second};
}

void qry3(ll j) {
cin>>qry[j].first>>qry[j].second;
ll id = res.size();

auto [pos, v] = last[qry[j].first];
if(pos != -1) eft[pos].push_back({id, qry[j].second});
res.push_back(v);
}

int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
ll tc = 1;
for(ll i = 1; i <= tc; i++) {
ll n, m, q;
cin>>n>>m>>q;
for(ll j = 0; j < q; j++) {
cin>>t[j];
if(t[j] == 1) qry1(j);
else if(t[j] == 2) qry2(j);
else if(t[j] == 3) qry3(j);
}
solve(m, q);
for(auto& r : res) cout<<r<<endl;
}
return 0;
}
Author: Song Hayoung
Link: https://songhayoung.github.io/2022/06/16/PS/AtCoder/abc253-f/
Copyright Notice: All articles in this blog are licensed under CC BY-NC-SA 4.0 unless stating additionally.