[LeetCode] Minimum Operations to Make Binary Array Elements Equal to One II

3192. Minimum Operations to Make Binary Array Elements Equal to One II

You are given a binary array nums.

You can do the following operation on the array any number of times (possibly zero):

  • Choose any index i from the array and flip all the elements from index i to the end of the array.

Flipping an element means changing its value from 0 to 1, and from 1 to 0.

Return the minimum number of operations required to make all elements in nums equal to 1.

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class Solution {
int helper(vector<int>& A, int x) {
int res = 0, n = A.size();
bool fl = false;
for(int i = 0; i < n; i++) {
int now = A[i];
if(fl) now = !now;
if(now != x) {
fl = !fl;
res++;
}
}
return res;
}
public:
int minOperations(vector<int>& A) {
return min(helper(A,1), helper(A,0) + 1);
}
};

Author: Song Hayoung
Link: https://songhayoung.github.io/2024/06/23/PS/LeetCode/minimum-operations-to-make-binary-array-elements-equal-to-one-ii/
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