Numbers that are a power of their sum of digits

• Time : $O(1)$
• Space : $O(1)$

python

def power_sumDigTerm(n):
    result=[81,512,2401,4913,5832,17576,19683,234256,390625,614656,1679616,17210368,34012224,52521875,60466176,205962976,612220032,8303765625,10460353203,24794911296,27512614111,52523350144,68719476736,271818611107,1174711139837,2207984167552,6722988818432,20047612231936,72301961339136,248155780267521,3904305912313344,45848500718449031,81920000000000000,150094635296999121,13744803133596058624,19687440434072265625,53861511409489970176,73742412689492826049,179084769654285362176]
    return result[n-1]