Next bigger number with the same digits
- Time : O(log(n))
- Space : O(log(n))
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| #include <bits/stdc++.h>
using namespace std;
vector<int> build(long n) {
vector<int> res;
while(n) {
res.push_back(n % 10);
n /= 10;
}
reverse(begin(res), end(res));
return res;
}
long nextBigger(long n) {
vector<int> perm = build(n);
next_permutation(begin(perm), end(perm));
long res = 0;
for(int i = 0; i < perm.size(); i++) res = res * 10 + perm[i];
return res > n ? res : -1;
}
|
