2660. Determine the Winner of a Bowling Game

You are given two 0-indexed integer arrays player1 and player2, that represent the number of pins that player 1 and player 2 hit in a bowling game, respectively.

The bowling game consists of n turns, and the number of pins in each turn is exactly 10.

Assume a player hit xi pins in the ith turn. The value of the ith turn for the player is:

• 2xi if the player hit 10 pins in any of the previous two turns.
• Otherwise, It is xi.

The score of the player is the sum of the values of their n turns.

Return

• 1 if the score of player 1 is more than the score of player 2,
• 2 if the score of player 2 is more than the score of player 1, and
• 0 in case of a draw.

class Solution {
public:
    int isWinner(vector<int>& player1, vector<int>& player2) {
        int a = 0, b = 0;
        int fl1 = 1, fl2 = 1;
        for(int i = 0; i < player1.size(); i++) {
            if((i and player1[i-1] == 10) or (i >= 2 and player1[i-2] == 10)) a += player1[i] *2 ;
            else a += player1[i];
        }
        for(int i = 0; i < player2.size(); i++) {
            if((i and player2[i-1] == 10) or (i >= 2 and player2[i-2] == 10)) b += player2[i] * 2;
            else b += player2[i];
        }
        return a > b ? 1 : a < b ? 2 : 0;
    }
};