Deserialize

• Time : $O(n)$
• Space : $O(n)$

c++

vector<string> Solution::deserialize(string A) {
    vector<string> res;
    string now = "";
    for(auto a : A) {
        if(isdigit(a)) continue;
        else if(a == '~') res.push_back(now), now = "";
        else now.push_back(a);
    }
    return res;
}