[Codeforces] Round #305 (Div. 2) B. Mike and Fun

Codeforces Round #305 (Div. 2) B. Mike and Fun

  • Time : O(q * (logm + nm / nm / 2))
    • each modify query takes O(logm)
    • expect percentage of delete query changes max range result is 1 / nm
    • if max range was deleted, re-calculate max value is O(nm)
    • so except re-calcuate max value is O(1)
  • Space : O(nm)
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#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

using namespace std;

struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};

// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);

// alias
using ll = long long;
using ld = long double;

// constants
const ld PI = 3.14159265358979323846; /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 505050;
const ll mod = 1e9 + 7;

// typedef
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;

// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define sz(x) ll((x).size())
#define pyes cout<<"YES\n";
#define pno cout<<"NO\n";
#define pneg1 cout<<"-1\n";
#define CASE(x) cout<<"Case #"<<x<<": ";

// utility functions
template <typename T>
void print(T &&t) { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<" ";cout<<"\n";}
//void readf() {freopen("", "rt", stdin);}

ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
ll __lcm(ll x, ll y) { return x * y / __gcd(x,y); }
ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

map<ll, ll> range[505];

ll dis(map<ll, ll>::iterator it) {
return it->second - it->first + 1;
}

ll insert(ll r, ll c) {
auto& mp = range[r];
auto it = mp.insert({c, c}).first;
if(it != begin(mp)) {
auto prv = prev(it);
if(prv->second == c - 1) {
prv->second = c;
mp.erase(it);
it = prv;
}
}
if(next(it) != end(mp)) {
auto nxt = next(it);
if(it->second + 1 == nxt->first) {
it->second = nxt->second;
mp.erase(nxt);
}
}
return dis(it);
}

ll remove(ll r, ll c) {
auto& mp = range[r];
auto it = prev(mp.upper_bound(c));
ll res = dis(it);

if(c == it->second and c == it->first) {
mp.erase(it);
} else if(c == it->second) {
it->second = c - 1;
} else if(c == it->first){
mp[c+1] = it->second;
mp.erase(it);
} else {
mp[c+1] = it->second;
it->second = c - 1;
}

return res;
}

ll find() {
ll res = 0;
rep(i,0,500) {
for(auto& [f, e] : range[i])
res = max(res, e-f+1);
}
return res;
}

vll solve(vvll& A, vpll Q) {
vll res;
ll ma = 0, n = sz(A), m = sz(A[0]);

vvll dp(n, vll(m));
rep(i,0,n) {
rep(j,0,m) {
if(A[i][j]) ma = max(insert(i,j), ma);
}
}

for(auto [r, c] : Q) {
r -= 1, c -= 1;
if(A[r][c]) {
auto prv = remove(r,c);
if(prv == ma) ma = find();
} else ma = max(ma, insert(r,c));
A[r][c] = !A[r][c];
res.push_back(ma);
}
return res;
}

int main() {
Code By Sumfi

cout.precision(12);

ll tc = 1;
//cin>>tc;
for (ll i = 1; i <= tc; i++) {
ll n,m,q;
cin>>n>>m>>q;
vvll A(n, vll(m));
vpll Q(q);
rep(i,0,n) rep(j,0,m) cin>>A[i][j];
rep(i,0,q) cin>>Q[i].first>>Q[i].second;
for(auto& r : solve(A,Q)) print(r);
}
return 0;
}
Author: Song Hayoung
Link: https://songhayoung.github.io/2022/07/20/PS/Codeforces/div2-305-b/
Copyright Notice: All articles in this blog are licensed under CC BY-NC-SA 4.0 unless stating additionally.