Codeforces Round #305 (Div. 2) B. Mike and Fun
- Time : O(q * (logm + nm / nm / 2))
- each modify query takes
O(logm)
- expect percentage of delete query changes max range result is
1 / nm
- if max range was deleted, re-calculate max value is
O(nm)
- so except re-calcuate max value is
O(1)
- each modify query takes
- Space : O(nm)
c++
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