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| #include <bits/stdc++.h>
#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")
using namespace std;
struct PairHash {
inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }
};
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);
using ll = long long;
using ld = long double;
const ld PI = 3.14159265358979323846;
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 101010;
const ll mod = 1e9+7;
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define pyes cout<<"Yes\n";
#define pno cout<<"No\n";
#define pneg1 cout<<"-1\n";
template <typename T>
void print(T &&t) { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<" ";cout<<"\n";}
ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
ll __lcm(ll x, ll y) { return x * y / __gcd(x,y); }
using namespace std;
vvll solve(vvll& A) {
ll n = A.size();
vvll res(2, vll(n));
rep(i,0,n - 1) {
ll d = A[i][0] - A[i+1][0];
rep(j, 0, n) {
if(A[i][j] - A[i+1][j] != d) return {};
}
}
rep(i,0,n) res[0][i] = A[i][0];
rep(i,0,n) res[1][i] = A[0][i] - res[0][0];
ll mi = *min_element(all(res[1]));
if(mi < 0) {
rep(i, 0, n) {
res[0][i] += mi;
res[1][i] -= mi;
if(res[0][i] < 0 or res[1][i] < 0) return {};
}
}
return res;
}
int main() {
Code By Sumfi
cout.precision(12);
ll tc = 1;
for (ll i = 1; i <= tc; i++) {
ll n;
cin>>n;
vvll A(n, vll(n));
rep(i,0,n) rep(j,0,n) cin>>A[i][j];
auto res = solve(A);
if(res.empty()) pno
else {
pyes
for(auto r : res) printv(r);
}
}
return 0;
}
|
