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| #include <bits/stdc++.h>
#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")
using namespace std;
struct PairHash {
inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }
};
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);
using ll = long long;
using ld = long double;
const ld PI = 3.14159265358979323846;
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 101010;
const ll mod = 1e9+7;
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
#define rep(i,n) for(ll i=0;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
ll __lcm(ll x, ll y) { return x * y / __gcd(x,y); }
using namespace std;
ll helper(vvll& G, vll& A, vll& B, ll now) {
ll res = 0;
if(now == 0) {
rrep(i, 1, min(A[0],B[0]) - 2) {
G[0][0] = i;
res += helper(G, A, B, now + 1);
G[0][0] = 0;
}
} else if(now == 1) {
rrep(i, 1, min(A[0] - G[0][0] - 1, B[1] - 2)) {
G[0][1] = i;
res += helper(G, A, B, now + 1);
G[0][1] = 0;
}
} else if(now == 2) {
rrep(i, 1, min(A[1] - 2, B[0] - G[0][0] - 1)) {
G[1][0] = i;
res += helper(G, A, B, now + 1);
G[1][0] = 0;
}
} else if(now == 3) {
rrep(i, 1, min(A[1] - G[1][0] - 1, B[1] - G[0][1] - 1)) {
G[1][1] = i;
res += helper(G, A, B, now + 1);
G[1][1] = 0;
}
} else if(now == 4) {
G[0][2] = A[0] - G[0][0] - G[0][1];
G[1][2] = A[1] - G[1][0] - G[1][1];
G[2][0] = B[0] - G[0][0] - G[1][0];
G[2][1] = B[1] - G[0][1] - G[1][1];
G[2][2] = B[2] - G[0][2] - G[1][2];
res = accumulate(all(G[2]), 0ll) == A[2] and G[2][2] > 0;
G[0][2] = G[1][2] = G[2][0] = G[2][1] = G[2][2] = 0;
}
return res;
}
ll solve(vll& A, vll& B) {
return helper(vvll() = {{0,0,0},{0,0,0},{0,0,0}}, A, B, 0);
}
int main() {
Code By Sumfi
cout.precision(12);
ll tc = 1;
for (ll i = 1; i <= tc; i++) {
vll A(3), B(3);
rep(i,3) cin>>A[i];
rep(i,3) cin>>B[i];
cout<<solve(A,B)<<endl;
}
return 0;
}
|
