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| #include <bits/stdc++.h>
#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")
using namespace std;
struct PairHash {
inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }
};
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);
using ll = long long;
using ld = long double;
const ld PI = 3.14159265358979323846;
const ll INF = 987654321987654321;
const ld EPS = 1e-9;
const ll MAX_N = 202020;
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
#define rep(i,n) for(ll i=0;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
ll __lcm(ll x, ll y) { return x * y / __gcd(x,y); }
using namespace std;
vll adj[MAX_N], radj[MAX_N];
ll vis1[MAX_N], vis2[MAX_N];
ll rep[MAX_N];
vll st;
void dfs(ll u) {
vis1[u] = true;
for(auto& v : adj[u]) {
if(!vis1[v])
dfs(v);
}
st.push_back(u);
}
void dfs2(ll u, ll r) {
rep[u] = r;
vis2[u] = true;
for(auto& v : radj[u])
if(!vis2[v])
dfs2(v, r);
}
ll solve(vll& X, vll& F) {
ll res = 0, n = X.size();
rep(i,n) {
adj[i].push_back(X[i]-1);
radj[X[i]-1].push_back(i);
}
rep(i,n) {
if(!vis1[i])
dfs(i);
}
while(!st.empty()) {
auto u = st.back(); st.pop_back();
if(!vis2[u]) dfs2(u,u);
}
umll mp, freq;
rep(i, n) {
if(!mp.count(rep[i]))
mp[rep[i]] = INF;
mp[rep[i]] = min(mp[rep[i]], F[i]);
freq[rep[i]]++;
}
for(auto& [k, v] : mp) {
if(freq[k] == 1) continue;
res += v;
}
return res;
}
int main() {
Code By Sumfi
ll tc = 1;
for (ll i = 1; i <= tc; i++) {
ll n;
cin>>n;
vll X(n), F(n);
rep(j,n)cin>>X[j];
rep(j,n)cin>>F[j];
cout<<solve(X,F)<<endl;
}
return 0;
}
|
