1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96
| #include <bits/stdc++.h>
#pragma optimization_level 3 #pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx") #pragma GCC optimize("Ofast") #pragma GCC target("avx,avx2,fma") #pragma GCC optimization ("unroll-loops")
struct PairHash {inline std::size_t operator()(const std::pair<int,int> & v) const {return v.first*31+v.second;}};
#define MAX_N 101010 #define INF 987654321 #define EPS 1e-9 #define ll long long #define pll pair<ll, ll> #define vpll vector<pll> #define vall3 vector<array<ll,3>> #define all3 array<ll,3> #define all5 array<ll,5> #define vall5 vector<all5> #define vll vector<ll> #define vi vector<int> #define vs vector<string> #define usll unordered_set<ll> #define uspll unordered_set<pll, PairHash> #define umll unordered_map<ll,ll> #define vvs vector<vs> #define vvll vector<vll> #define all(a) begin(a), end(a) #define rall(a) rbegin(a), rend(a)
ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
using namespace std;
string solve(vpll& A, vpll& B) { sort(all(A)); sort(all(B));
ll n = A.size(), m = B.size(); priority_queue<ll> a, b; ll i = 0, j = 0;
while(i < n and j < m) { ll ah = A[i].first; while(j < m and B[j].first < ah) { b.push(B[j++].second); } queue<ll> tmp; while(!a.empty() and !b.empty()) { if(b.top() >= a.top()) { b.pop(); a.pop(); } else { tmp.push(a.top()); a.pop(); } } while(!b.empty()) b.pop(); while(!tmp.empty()) { a.push(tmp.front()); tmp.pop(); }
while(i < n and ah == A[i].first) { a.push(A[i++].second); } }
while(j < m) b.push(B[j++].second); while(!a.empty() and !b.empty() and b.top() >= a.top()) { a.pop(); b.pop(); }
return a.empty() ? "Yes" : "No"; }
int main() { ios_base::sync_with_stdio(0); ios::sync_with_stdio(0); cin.tie(0); ll tc = 1; for(ll i = 1; i <= tc; i++) { ll n, m; cin>>n>>m; vpll A(n), B(m); for(ll j = 0; j < n; j++) cin>>A[j].first; for(ll j = 0; j < n; j++) cin>>A[j].second; for(ll j = 0; j < m; j++) cin>>B[j].first; for(ll j = 0; j < m; j++) cin>>B[j].second; cout<<solve(A,B)<<endl; } return 0; }
|