1480. Running Sum of 1d Array

Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).

Return the running sum of nums.

class Solution {
public:
    vector<int> runningSum(vector<int>& nums) {
        vector<int> res{nums[0]};
        for(int i = 1; i < nums.size(); i++)
            res.push_back(res.back() + nums[i]);
        return res;
    }
};