[BOJ] 10000 원 영역

원 영역

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#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

#define MAX_N 505
#define INF 987654321
#define ll long long
#define pll pair<ll, ll>
#define vpll vector<pll>
#define vall3 vector<array<ll,3>>
#define all5 array<ll,5>
#define vall5 vector<all5>
#define vll vector<ll>
#define vs vector<string>
#define usll unordered_set<ll>
#define vvs vector<vs>
#define vvll vector<vll>
#define all(a) begin(a), end(a)

using namespace std;

struct Point {
ll x, y;
};
vector<Point> p;
ll n;

void helper(ll &i, ll& res) {
ll r = p[i].y * 2, ed = p[i++].x + r;
res++;
while(i < n and p[i].x < ed) {
r -= p[i].y * 2;
helper(i, res);
}
if(!r) ++res;
}

ll solve() {
sort(all(p), [](const Point &a, const Point &b) {
if (a.x == b.x) return a.y > b.y;
return a.x < b.x;
});
ll res = 1, i = 0;
while(i < n) {
helper(i, res);
}
return res;
}

int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.setf(ios::fixed);
cout.precision(8);
cin >> n;
for (ll i = 0, x, y; i < n; i++) {
cin >> x >> y;
p.push_back({x - y, y});
}
cout << solve() << '\n';

return 0;
}

Author: Song Hayoung
Link: https://songhayoung.github.io/2022/05/04/PS/BOJ/10000/
Copyright Notice: All articles in this blog are licensed under CC BY-NC-SA 4.0 unless stating additionally.