[BOJ] 10937 두부 모판 자르기

두부 모판 자르기

  • dp solution
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#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

#define MAX_N 1010
#define ll long long
#define pll pair<ll, ll>
#define vpll vector<pll>
#define vall3 vector<array<ll,3>>
#define vll vector<ll>
#define vs vector<string>
#define usll unordered_set<ll>
#define vvs vector<vs>
#define vvll vector<vll>
#define all(a) begin(a), end(a)
using namespace std;

ll n;
ll table[4][4] {{100,70,40,0},{70,50,30,0},{40,30,20,0},{0,0,0,0}};
ll matrix[11][11];
ll dp[121][1<<12];

ll cvt(char ch) {
if(ch == 'A') return 0;
if(ch == 'B') return 1;
if(ch == 'C') return 2;
return 3;
}

ll solve(ll mask, ll p) {
if(p == n * n) return 0;
if(dp[p][mask] != -1) return dp[p][mask];

ll& res = dp[p][mask] = solve((mask<<1) % (1<<(n+1)), p + 1);
ll y = p / n, x = p % n;

if(!(mask & (1<<n))) {
if(x + 1 < n and !(mask & (1<<(n-1)))) {
res = max(res, table[matrix[y][x]][matrix[y][x+1]] + solve((mask<<2) % (1<<(n+1)), p + 2));
}
if(y + 1 < n and !(mask & 1)) {
res = max(res, table[matrix[y][x]][matrix[y+1][x]] + solve(((mask|1)<<1) % (1<<(n+1)), p + 1));
}
}
return res;
}

int main() {
cin>>n;
char ch;
for(ll i = 0; i < n; i++)
for(ll j = 0; j < n; j++) {
cin>>ch;
matrix[i][j] = cvt(ch);
}
memset(dp, -1, sizeof dp);
cout<<solve(0,0)<<endl;
return 0;
}
  • mcmf solution
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#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

#define MAX_N 404
#define ll long long
#define pll pair<ll, ll>
#define vpll vector<pll>
#define vall3 vector<array<ll,3>>
#define vll vector<ll>
#define vs vector<string>
#define usll unordered_set<ll>
#define vvs vector<vs>
#define vvll vector<vll>
#define all(a) begin(a), end(a)
using namespace std;

ll n, gap = 123, blue = 1, green = 1, source = 301, sink = 302;
ll table[4][4] {{100,70,40,0},{70,50,30,0},{40,30,20,0},{0,0,0,0}};
ll matrix[11][11], id[11][11], path[MAX_N], cost[MAX_N][MAX_N], cap[MAX_N][MAX_N], flo[MAX_N][MAX_N];
vll adj[MAX_N];

ll cvt(char ch) {
if(ch == 'A') return 0;
if(ch == 'B') return 1;
if(ch == 'C') return 2;
return 3;
}

ll c(ll y1, ll x1, ll y2, ll x2) {
return table[matrix[y1][x1]][matrix[y2][x2]];
}

bool bfs(ll u, ll v) {
bool inc[MAX_N];
vll w(MAX_N, 987654321);
memset(path, 0, sizeof path);
memset(inc, 0, sizeof inc);
queue<ll> q;
q.push(u);
w[u] = 0;
inc[u] = true;

while(!q.empty()) {
ll n = q.front(); q.pop();
inc[n] = false;
for(auto& m : adj[n]) {
if(cap[n][m] - flo[n][m] > 0 and w[n] + cost[n][m] < w[m]) {
w[m] = w[n] + cost[n][m];
path[m] = n;
if(!inc[m]) {
inc[m] = true;
q.push(m);
}
}
}
}

return path[v] != 0;
}

ll solve() {
for(ll i = 0; i < n; i++) {
for(ll j = 0; j < n; j++) {
if((i + j) & 1) continue;
ll me = id[i][j];
ll dy[4]{-1,0,1,0}, dx[4]{0,1,0,-1};
for(ll k = 0; k < 4; k++) {
ll ny = i + dy[k], nx = j + dx[k];
if(0 <= ny and ny < n and 0 <= nx and nx < n) {
ll you = id[ny][nx];
cost[me][you] = -c(i,j,ny,nx);
cost[you][me] = c(i,j,ny,nx);

cap[me][you] = 1;

adj[me].push_back(you);
adj[you].push_back(me);
}
}
}
}

for(ll i = 1; i < blue; i++) {
adj[source].push_back(i);
adj[i].push_back(source);

cap[source][i] = 1;
}

for(ll i = 1; i < green; i++) {
adj[i + gap].push_back(sink);
adj[sink].push_back(i + gap);

cap[i + gap][sink] = 1;
}

ll res = 0;
while(bfs(source, sink)) {
ll v = sink, mi = INT_MAX;
while(source != v) {
ll u = path[v];

mi = min(mi, cap[u][v] - flo[u][v]);

v = u;
}

v = sink;
ll sum = 0;
while(source != v) {
ll u = path[v];

sum += mi * cost[u][v];

flo[u][v] += mi;
flo[v][u] -= mi;

v = u;
}
res += min(sum, 0ll);
}
return -res;
}

int main() {
cin>>n;
char ch;
for(ll i = 0; i < n; i++) {
for (ll j = 0; j < n; j++) {
cin >> ch;
matrix[i][j] = cvt(ch);
id[i][j] = ((i + j) & 1) ? green++ + gap : blue++;
}
}
cout<<solve()<<endl;
return 0;
}
Author: Song Hayoung
Link: https://songhayoung.github.io/2022/04/28/PS/BOJ/10937/
Copyright Notice: All articles in this blog are licensed under CC BY-NC-SA 4.0 unless stating additionally.