[BOJ] 16932 모양 만들기

Time Lapse :15min 2sec

16932.cpp

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#include <iostream>
#include <algorithm>
#include <queue>
#include <vector>
using namespace std;
int map[1000][1000];
int dy[4] = {-1,0,1,0};
int dx[4] = {0,1,0,-1};
int sz[500*500 + 2];
int island = 2, n, m, ans = 0;
int main(void) {
scanf("%d %d", &n, &m);
for (int i = 0; i < n; ++i)
for (int j = 0; j < m; ++j)
scanf("%d", &map[i][j]);

for (int i = 0; i < n; ++i)
for (int j = 0; j < m; ++j) {
if (map[i][j] == 1) {
int cnt = 1;
queue<pair<int, int>> q;
q.push(make_pair(i, j));
map[i][j] = island;
while (!q.empty()) {
pair<int, int> p = q.front();
q.pop();
for (int k = 0; k < 4; ++k) {
int nx = p.second + dx[k];
int ny = p.first + dy[k];
if (0 <= nx && nx < m && 0 <= ny && ny < n && map[ny][nx] == 1) {
map[ny][nx] = island;
++cnt;
q.push(make_pair(ny, nx));
}
}
}
sz[island++] = cnt;
}
}
for (int i = 0; i < n; ++i)
for (int j = 0; j < m; ++j)
if (!map[i][j]) {
int cmp = 1;
int visit[4] = {-1, -1, -1, -1};
for (int k = 0; k < 4; ++k) {
int nx = j + dx[k];
int ny = i + dy[k];
if (0 <= nx && nx < m && 0 <= ny && ny < n) {
bool flag = true;
for (int l = 0; l < k; ++l)
if (map[ny][nx] == visit[l])
flag = false;
if (flag) {
cmp += sz[map[ny][nx]];
visit[k] = map[ny][nx];
}
}
}
ans = max(ans, cmp);
}
printf("%d", ans);
}
Author: Song Hayoung
Link: https://songhayoung.github.io/2020/08/27/PS/BOJ/16932/
Copyright Notice: All articles in this blog are licensed under CC BY-NC-SA 4.0 unless stating additionally.